Question

silver crystallises in fcc lattice. if edge length of the cell is 4.07×10^-8cm and density is 10.5g cm^-8.calculate the atomic mass of the silver​

Answer 1

106.5 gmol⁻¹    

Explanation:

Given, cell is FCC, z = 4

Edge length = 4.07 × 10⁻⁸, NA =  6.02 × 10²³

Mass of metal = d × NA × a³/z

                        = 10.5 × 6.02 × 10²³ × (4.07 × 10⁻⁸)³/4

                        = 426.15/4

                        = 106.5 gmol⁻¹