Question

Silver crystallises into a fcc structure. If density of silver is 10.51 g cm -3 . Calculate the volume of unit cell. Atomic mass of silver is 108 g mol-1 .

Answer 1

Answer: The volume of unit cell is 6.834*10^-23 cm^3

Explanation:

Formula that will be used here is:

Density = (Z*Molar Mass)/ (Volume * Avogadro no.)

Now in FCC structure the value of Z=4

Molar Mass of Silver= 108g/mol

$avogadro \: number = 6.022 \times {10}^{23}$

Density(given)= 10.51 g/cm^3

Now using formula,

Volume= (Z* Molar mass)/ Density* Avogadro no.

= (4*108)/10.51*6.022*10^23

$6.834 \times {10}^{ - 23} \: {cm}^{3}$