silver crystallizes in a face lattice. The edge
length of its whit cell is 4 0778 108 cm and
its density is 10.5g cm? calculate this
basis the atomic mass of silver
CNA 6.02 x 1023 molo
Answers
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Answer:
40778108 ÷ 10.5g = 3883629.33333
60.2 × 1023 = 62126.4
3883629.33333 + 62126.4 = 3945755.73333
=3945755.73333
Explanation:
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