Question

Silver crystallizes in face centered cubic unit cell. Each side of the unit cell has a length of 400 pm. Calculate the
radius of the Silver atom.

Answer 1

this is your answer for question

Answer 2

$\huge\rm\underline\purple{Question :-}$

Silver crystallizes in face centered cubic unit cell. Each side of the unit cell has a length of 400 pm. Calculate the radius of the Silver atom.

$\huge\rm\underline\purple{Answer :-}$

$\orange{\underline\bold{Given,}}$

✏ Silver crystallizes in FCC unit cell.

✏ So, r = $\frac{a}{2\sqrt2}$

where r is the radius of the silver atom

and a is the edge length.

$\red{\underline\bold{To \:find,}}$

• Radius of the Silver atom, r = ?

$\green{\underline\bold{Now,}}$

Edge length = 400 pm

= 400 × 10^-10 cm

$\blue{\underline\bold{Thus,}}$

r = $\frac{400 × 10^-10}{2 × 1.414}$

r = 141.44 × 10^-10 cm

r = 141.4 pm

$\pink{\underline\bold{∴\:The \:radius\:of\:the\:silver\: atom\: was \:found \:to\: be\: 141.4 \:pm}}$

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