Question

Silver crystallizes in the fcc (face-centered cubic) system with a lattice parameter a =408.56 pm and its density is ρ = 10490 Kg / m3. Calculate the number of cells per cm 3 ; the number of atoms per m 3

Answer 1

Answer:

The edge length of the unit cell, a=408.7pm =408.7×10

−10

cm

Atomic mass of silver, M= 108 g mol

−1

N

A

=6.022×10

23

mol

−1

The number of atoms in the unit cell of a FCC structure, n=4

Density of silver,

=

N×a

3

n×M

=

6.022×10

23

mol

−1

×(408.7×10

−10

cm)

3

4×108gmol

−1

Density of silver =10.51g/cm

3