Chemistry, asked by diganthmd, 6 months ago

silver forms a fcc lattice and x-ray diffraction studies of its crystal shows that the edge length of its unit cell is 406 picometre calculate the density of silver (atomic mass ag is 107 u)

Answers

Answered by ronininsurgent

1

Explanation:

d=zM/a^3Na

in FCC z=4

M=107

a=406 ×10^-10 cm

Na(avogardos constant)

d= 4× 107/( 406×10^-10)^3 × 6.022× 10^23

d= 10.65 g/cm^3

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