Question

silver forms CCP lattice and x- ray studies of its crystals shows that the edge length of its unit cell is 408.6 pm calculate the density of silver(atomic mass=107.9 u)​

Answer 1

Answer:

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Answer 2

Silver forms cubic close packing (ccp) , therefore the number of silver atoms per unit cell z=4

Molar mass of silver M=107.9 gmol−1 =

107.9×10−3kgmol−1

Edge length of unit cell a=408.6 pm =. 408.6×10−12

Density d=(z.M)/(a3.NA)

d=4×(107.9×10−3kgmol−1(408.6×10−12m)3(6.022×1023mol−1) =10.5×103kgm−3 d=10.5gcm−3

hope it will help u