Question

. Silver has a resistivity of 1.6 × 10–8 m. If you make a silver wire that's 10 m long with an area of 3 × 10–6 m2, what is the wire's resistance?

Answer 1

Answer:

R=0.008{\text{\O}mega}0.008Ømega

Step-by-step explanation:

It is given that the electrical resistivity of silver is 1.60 x 10-6Ω m and cross-sectional area 2{\times}10^{-3}m^{2}2×10

−3

m

2

.

We know that R=\frac{{\rho}d}{A}

A

ρd

=\frac{(1.60{\times}10^{-6}){\times}10}{2{\times}10^{-3}}

2×10

−3

(1.60×10

−6

)×10

=\frac{1.60{\times}10^{-6}{\times}10}{2{\times}10^{-3}}

2×10

−3

1.60×10

−6

×10

=8{\times}10^{-3}{\text{\O}mega}8×10

−3

Ømega

=8{\times}\frac{1}{1000}{\text{\O}mega}8×

1000

1

Ømega

R=0.008{\text{\O}mega}0.008Ømega