Question

Silver is electrodeposited on a metallic vessel of surface area 800 cm2 by passing
current of 0.2 A for 3 hours. Calculate the thickness of silver deposited.

Answer 1

Answer:

2.88x10^-4 cm is the thickness of silver deposited.

Explanation:

Given

Silver is electrodeposited on a metallic vessel.

Surface area = 800 cm^2

It is done by passing current.

current =0.2 A

time =3 hours.

To Calculate : the thickness of silver deposited.

Solution:

The given element is Ag that is silver

Atomic mass of Ag = 107.92g

Current = 0.2A

Time= 3hours = 3*60*60= 10800 secs

Electric charge= current*time

=0.2 x 10800

= 2160 Colombs

It is a fact that 1A will give 96500 C will deposit 107.92 g of Ag

total Ag deposited from 2160 C will be given by

=(107.92/96500) * 2160

=233,107.2/96500

= 2.4156 gms

Hence now

density of Ag =10.47 g/cubic cm

Now we will calculate volume of silver deposited

Volume of Ag deposited

= Mass / Density =

2.4156 / 10.47

= 0.2307 cubic centimeters

Now finally thickness deposited will be calculated by

thickness deposited = Volume / area

= 0.2307/ 800

= 2.88x10^-4 cm

This thickness = 2.88x10^-4 cm

Hence, 2.88x10^-4 cm is the thickness of silver deposited.

Answer 2

Answer :

2.95 × 10⁻⁴ cm

Explanation :

Given :

Current, I = 0.2 A

Time, t = 3 hrs

= (3 × 60 × 60) sec

= 10800 sec

As we know,

• Charge = Current × Time

Q = I × t

Putting values, we get

Q = (0.2)(10800)

= 2160 C

Now,

Mass of silver deposited by passing 96487 C charge = 108 g

Mass of silver deposited by passing 1 C charge = (108/96487) g

Mass of silver deposited by passing 2160 C charge = [ (108/96487) × 2160 ] g

= 2.417 g

Density of silver = 10.47 g/cm³ (given)

Mass of silver = 2.417 g

• Volume of silver = Mass of silver/Density of silver

Putting values, we get

Volume of silver = (2.417/10.47) cm³

= 0.236 cm³

We can also write volume as :

• Volume of silver = Area of silver × Length (Thickness) of silver

Thickness of silver = Volume of silver/Area of silver

Area of silver = 800 cm² (given)

Volume of silver = 0.236 cm³

Putting values, we get

Thickness of silver = (0.236/800) cm

= 2.95 × 10⁻⁴ cm