Silver nitrate is gradually added to an aqueous solution containing 0.01 m each of chloride bromide and iodide ions. The correct sequence (decreasing order) in which the halides will be precipitated is
Answers
The correct sequence will be AgI, AgBr and then AgCl.
The silver ions in the silver nitrate will react with the chloride, bromide and iodide ions to make the respective salt.
The equation can be given below:
Ag⁺ + Cl⁻ = AgCl
Ag⁺ + Br⁻ = AgBr
Ag⁺ + l⁻ = Agl
The solubility product constant of the three halides is given below:
Ksp of AgI = 8.3 x 10⁻¹⁷
Ksp of AgBr = 5.4 x 10⁻¹³
Ksp of AgCl = 1.77 x 10⁻¹⁰
Since the Ksp of AgI is least hence it will be precipitated first, then AgBr and then AgCl
Answer:
Explanation:
Ag+ is a soft cation or acid due to large size & small charge and I- is a soft anion or base, so, bonding between them is strong and AgI will be precipitated most readily whereas Cl- is a hard base and AgCl will be most soluble out of the three & will precipitated at last.