Question

Silver nitrate solution was mixed with 5g of sodium chloride solutions to verify law of conservation of mass.8.1 gram of silver chloride was formed and sodium nitrate formed was equal to half of the amount of silver nitrate solution used. What is the amount of AgNO3 used and NaNO3 formed.​

Answer 1

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✏️Question:-

→Silver nitrate solution was mixed with 5g of sodium chloride solutions to verify law of conservation of mass.8.1 gram of silver chloride was formed and sodium nitrate formed was equal to half of the amount of silver nitrate solution used. What is the amount of AgNO3 used and NaNO3 formed.

✏️ Answer:-

→AgNO3 used = 6.2 g and

→NaNO3 formed = 3.1 g

✏️Explanation:-

→AgNO3 + NaCl = AgCl + NaNO3x g

5 g = 8.1 + y

Since y =x²

And the given equation obeys the law of mass action x + 5 = 8.1 + x²

x − x² = 8.1 − 5x² = 3.1x = 3.1 × 2 = 6.2 gy =x2 = 6.22 = 3.1

Now,

Substitute and verify the law of mass action:-

6.2 + 5 = 8.1 + 3.111.2 g = 11.2 g

So

AgNO3 used = 6.2 g and

NaNO3 formed = 3.1 g

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Answer 2

Answer:

yo heres the answer

Explanation:

AgNO3 used = 6.2 g and

→NaNO3 formed = 3.1 g

✏️Explanation:-

→AgNO3 + NaCl = AgCl + NaNO3x g

5 g = 8.1 + y

Since y =x²

And the given equation obeys the law of mass action x + 5 = 8.1 + x²

x − x² = 8.1 − 5x² = 3.1x = 3.1 × 2 = 6.2 gy =x2 = 6.22 = 3.1

Now,

Substitute and verify the law of mass action:-

6.2 + 5 = 8.1 + 3.111.2 g = 11.2 g

So

AgNO3 used = 6.2 g and

NaNO3 formed = 3.1 g