Silver this plzzz. .. . . it's my homework plzzzz . . solve it ..
Attachments:
Answers
Answered by
1
hey mate here is your answer
p(power)= 400 watt = .4kW
t= 8 hours per day
energy consumed one day = power × time
E=.4×8
=3.2kWh
energy consumed in 30 days = 30× 3.2
=96kWh
Cost = rate × energy consumed
= 3.00×96
=288.00 rupees.
it will surely help you.
Plse mark answer as brainliest if u like ❤❤❤ and follow me .
divyaman44:
plse mark answer as brainliest if u like
Answered by
1
The total energy consumed by the refrigerator in 30 days =400W×8hours×30 days
=96000Wh
=96kW h
the cost of energy to operate the refrigerator for 30 days =96kW h×Rs.3 per kW h
=Rs. 288
HOPE IT WILL HELP YOU ✌ ✌
Similar questions