simflify / 27 * x ^ 3 - (x - y) ^ 3
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Step-by-step explanation:
(3x)^3-(3x-y)^3
= [3x-(3x-y)][(3x)^2+3x(3x-y)+(3x-y)^2]
=(3x-3x+y)[9x^2+9x^2-3xy+9x^2-6xy+y2]
=(y)[27x^2-9xy+y^2]
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So this is mine answer. If it's right then click on thank you and if it's wrong then please mention
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