Question

simify 2√3+3√2\2√3-3√2+5+2√6
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Answer 1

Answer:

(i) (3+3–√)(2+2–√)

3(2+2–√)+3–√(2+2–√)

=6+32–√+23–√+6–√

(ii) (3+3–√)(3−3–√)

=3(3−3–√)+3–√(3−3–√)

=9−33–√+33–√−(3–√)2

=9−3=6

(iii) (5–√+2–√)2

=(5–√)2+(2–√)2+2(5–√)(2–√)

=5+2+210−−√

=7+210−−√

(iv) (5–√−2–√)(5–√+2–√)

=(5–√)2−(2–√)2

using identity (a+b)(a−b)=a2−b2

=5−2=3

Step-by-step explanation: