Question

Similar buckets are available in two sizes.
The large bucket has height 30 cm and base diameter 16 cm.
The small bucket has base diameter 8 cm.
(a) Find the height of the small bucket.​

Answer 1

Answer:

The height of the small bucket will be 72cm.

Step-by-step explanation:

for the first bucket,

h= 30cm , d = 16cm , r = 8cm

area of cylinder = 2

$2\pi \: rh \: + 2\pi \: r {}^{2}$

now putting the values there we get

2 × 22/7 × 8 × 30 + 2 × 22/7 × 64

= 1508.57 + 402. 28

= 1910.85 cm.sq

now for the other bucket ; since they are similar

d = 8cm , r = 4cm

$2\pi \: r( \: h + r) \: = 1910.85 \: cm.sq$

now putting all the values, we get

2 × 22/7 × 4 ( h + 4 ) = 1910.85

= 25. 14 ( h + 4 ) = 1910.85

= h + 4 = 1910.85

25.4

= h = 76 - 4

h = 72 cm

Answer 2

The height of the small bucket is 15cm.

Given:

Two similar buckets in two different sizes.

To Find:

The height of the small bucket

Solution:

Since the two buckets are similar. Therefore, the ratio of the heights of the bucket to the diameter of the bucket is equal for both buckets.

Let h be the height of a small bucket

$\frac{30}{16} =\frac{h}{8} \\\\h = \frac{30 \times 8}{16}\\\\h = 15 \ cm$

Therefore, the height of the small bucket is 15cm.

#SPJ2

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