Math, asked by shaiksaidulu4914, 1 month ago

Similar Triangles 211 TRY THIS 1. Are triangles formed in each figure similar? Ifso, name the criterion of similarity. Write the similarity relation in symbolic form. (1) () 31 H M R 'K 10 (ii) 2 2 (iv) 3 AY X 3 5 w 3 В. C C (v) (vi) 400 600 B 800 B460° 809c 40° Р Р A cm. 70° 5 cm. (vii ) (viii 6 ст. . 70° R 5 cm. 2 cm. Qocm. 3 cm. 6 cm. R B B 2 cm. 4 cm. B4 C


plz.. answer the iv one fastly​

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Answers

Answered by tanvi692
6

Step-by-step explanation:

(i) Yes, by AA criteria FGH~KIH

(ii) Not similar

(iii) Yes, by SAS criteria AXY~ABC

(iv) Not similar

(v) Yes, by AA criteria AOQ~BOP

(vi) sry but picture is not full

(vii) Not similar

(viii) Not similar

Answered by rishkrith123
9

Answer:

(iv) the triangles are similar.

Step-by-step explanation:

(i) From ΔFGH and ΔHIK

  •    ∠H = ∠H (opposite angles)    
  •    ∠I = ∠G   (as IK and FG are parallel and IG is transversal)

So, from AA criterion for similarity of triangles

           ΔFGH similar to ΔHIK

(ii) From ΔPQR and ΔMNL

  • ∠Q = ∠M = 90°
  • But  \frac{PQ}{LM}\neq \frac{QR}{MN}  i.e.  \frac{6}{3}\neq \frac{10}{4}

So, ΔPQR is not similar to ΔMNL

(iii) From ΔAXY and ΔABC

  • ∠A = ∠A (common angle)
  • \frac{AX}{AB} = \frac{AY}{AC} = (\frac{2}{5} = \frac{2}{5}   )

So, ΔAXY is similar to ΔABC

(iv) From ΔAPJ and ΔABC

  • ∠A = ∠A (common angle)
  • \frac{AP}{AB} = \frac{AJ}{AC}  =(\frac{3}{8} = \frac{2}{\frac{16}{3} }=\frac{3}{8})

So, ΔAPJ is similar to ΔABC

(v) From ΔOAQ and ΔOPB

  • ∠O = ∠O (common angle)
  • ∠A = ∠B = 90° (Given)

So, ΔOAQ is similar to ΔOPB

(vi) The picture is not clear!!, but you can do it yourself now from above              conclusions

(vii) From ΔABC and ΔPQR

  • (\frac{AB}{PQ}=\frac{2}{5}  )\neq (\frac{BC}{QR}=\frac{2}{4}  )

So, ΔABC is not similar to ΔPQR

(viii) From ΔABC and ΔPQR

  • ∠A = ∠P (Given)
  • (\frac{AB}{PQ}= \frac{6}{2.5}  )\neq (\frac{AC}{PR}= \frac{10}{5}  )

So, ΔABC is not similar to ΔPQR

#SPJ3

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