simlify (a+2b+3c)square
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Generally (a+b+c)^2 = a^2+b^2+c^2+2(ab+bc+ca).
Consider a = a, b = 2b, c = 3c
(a+2b+3c)^2 = a^2+4b^2+9c^2+2(2ab+6bc+3ca).
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(a+2b+3c)^2
(a)^2+(2b)^2+(3c)^2 +2×a×2b+2×2b×3c+2×3c×a
a^2+4b^2+9c^2+4ab +12bc+6ac
(a)^2+(2b)^2+(3c)^2 +2×a×2b+2×2b×3c+2×3c×a
a^2+4b^2+9c^2+4ab +12bc+6ac
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