simlify and give reasons: (4^3 + 2^-1 + 3^-1)
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Answer:
[/tex]=4 ^{3} + \frac{1}{2} + \frac{1}{3} \\ = \frac{64 + 3 + 2}{6} \\ =\frac{69}{6} = \frac{23}{2} [/tex]
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Answer:
4³+2^-1+3^-1 = 64+1/2+1/3 = 389/6
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