Question

simlify Y=(A+B)(A+C')(B'+C')​

Answer 1

Answer:

(A + B) (A + C’) (B' + C’)

Apply distributive law on first two sum terms.

(A+BC’)(B’+C’)

multiply this

AB’+AC’+BB’C’+BC’ C’

BB’=0 and C’C’ =C’ So we will get

AB’+AC’+BC’

Write AB’ as B’A

B’A+BC’+AC’

Apply consensus theorem ( xy+x’z+yz= xy+x’z) on the above equation

B’A+BC’ ( Remove AC’ which is redundant based on consensus theorem.)

So Final answer is AB’+BC’

Step-by-step explanation:

hope it was helpful please make me brainliest

Answer 2

Answer:

y=(A+B)(A+C)(b+c)

y=2A+2B+2C

so it is no possible so not equal

Hope you understand

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