simlpfy 3(7xsquare+11x+8)and find the value for x=1and x=0
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3(7x²+11x+8)
For x=1
3[(7×1)+11+8]
3(26)
78
hence,
for x=1 value is 78
For x=0
3[(7×0²)+0+8]
3(8)
24
hence,
for x=0 value is 24
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