Question

simlyfy the following problem first​

Answer 1

a^m × a^n = a^(m+n)

let's use that in here

let's look at the numerator first

n is the base everywhere, so we have our numerator as n^(m+n+n+2+c+m) = n^(2m+2n+2+c)

let's see the denominator

the denominator has the base n everywhere, so the denominator will be

n^(m+n+c)

now we know (a^m)^n = a^(mn)

so our denominator will be

n^(2m+2n+2c)

our equation is now n^(2m+2n+2+c)/n^(2m+2n+2c)