Simon is making wreaths to sell.He has 60 bows,36 silk roses,and 48 silk carnations.He wants to put the same number of items on each wreath.All the items on a wreath will be the same type.How many items can Simon put on each wreath?
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He has 60 bows, 36 silk roses, and 48 silk carnations.
Now, to calculate how many items simon can put on each wreath, we need to find out H.C.F of 60, 36 and 48.
We know,
60=2*2*3*5
36=2*2*3*3
48=2*2*2*2*3
So, the highest common factors among 60, 36 and 48=2*2*3=12
Hence, H.C.F of 60,36, and 48=12
Therefore, Simon can put 12 items on each wreath to have the same number of items on each wreath.
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