Simon jogs from one end A to the other end B of a straight road of 80m long. He covers 160m in 2 minutes by turns around and comes back to A. Find average speed and average velocity of Simon.
Answers
Answer:
Explanation:
Average speed = total distance / total time
Average speed (A) = Distance from A to B/time
= 300 m / 2min 30sec
= 300m / 150sec
= 2m per second
Average velocity A is also same(300m/150sec) as displacement and the distance are same.
Average speed (B) = (Distance from A to B + Distance from B to C) / Total time
Total distance (A to C) = 300 + 100 m = 400m
Total time = 2min 30sec + 1min = 210sec
Therefore,
Average speed = 400m / 210 sec
= 40m per 21sec
Average velocity (B) = Displacement / time
Displacement (A to C) = +300 - 100 m (As Amit jogs back in same path in opposite direction)
Displacement (A to C) = 200 m
Time = 210 sec
Therefore,
Average velocity = 200m / 210 sec
= 20m / 221sec
I hope this will help you friend.
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