Question

simpify:- (1^3+2^3+3^3)^1÷2​

Answer 1

${( {1}^{3} + {2}^{3} + {3}^{3} )}^{ \frac{1}{2} } \\ \\ \sqrt{ {1}^{3} + {2}^{3} + {3}^{3}} \\ \\ \sqrt{1 + 8 + 27} = \sqrt{36} = 6$

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Answer 2

(1³+2³+3³)^½

=(1+8+27)^½

=(36)^½

=(6²)^½

=(6)²×½

=6