Question

simpify-m²-n²/(m+n)²×m²+mn+n²/m³-n³​

Answer 1

Answer:

(m^3-n^3) - m(m^2-n^2) + n(m-n)^3

= (m-n)(m^2+mn+n^2) - m(m+n)(m-n) + n(m-n)(m-n)(m-n)

= (m-n)[(m^2+mn+n^2) - m(m+n) + n(m-n)(m-n)]

= (m-n)[m^2+mn+n^2 - m^2-mn + n(m^2–2mn+n^2)]

= (m-n)[m^2+mn+n^2 - m^2-mn + m^2 n–2mn^2+n^3]

= (m-n)[n^2+m^2 n-2mn^2+n^3]

= n(m-n)[n + m^2 - 2mn + n^2]

= n(m-n)[n + (m-n)^2]. Answer

Step-by-step explanation:

hope it helps

Answer 2

Answer:

n(m-n)[n+(m-n)²]

Step-by-step explanation:

.................................