simpify the (a-b) (b-c) (c-a)
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Answer:
where is the value please ask full question
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Step-by-step explanation:
✏Given here
↪(a-b)(b-c)(c-a)
= (ab-ac-b²+bc)(c-a)
= (abc-a²b-ac²+a²c-b²c+ab²+bc²-abc
= (-a²b-ac²+a²c-b²c+ab²+bc²)
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