Question

simpilfy (m/2n+2n/m)^2-(m/2n-2n/m)^2-4 please answer me fast I'll mark u as brainliest

Answer 1

Answer:

Final result :

-m2 + 2m - 4n2

Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

(((((m+n)•2)-((m-n)•2))+((m-2n)•2))-(m2))-22n2

STEP

2

:

Equation at the end of step

2

:

(((((m+n)•2)-((m-n)•2))+2•(m-2n))-m2)-22n2

STEP

3

:

Equation at the end of step 3

(((((m+n)•2)-2•(m-n))+2•(m-2n))-m2)-22n2

STEP

4

:

Equation at the end of step 4

(((2•(m+n)-2•(m-n))+2•(m-2n))-m2)-22n2

STEP

5

:

STEP

6

:

Pulling out like terms

6.1 Pull out like factors :

-m2 + 2m - 4n2 = -1 • (m2 - 2m + 4n2)

Trying to factor a multi variable polynomial :

6.2 Factoring m2 - 2m + 4n2

Try to factor this multi-variable trinomial using trial and error

Factorization fails

Final result :

-m2 + 2m - 4n2

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Answer 2

Step-by-step explanation:

(m/2n+2n/m)^2-(m/2n-2n/m)^2-4

we will solve two expressions first

(m) ^2+(2n)^2/(2n)^2+(m)^2

every number will divide itself

so, it will be zero

same with the second expression=0

Now,

0-0-4=-4