Question

simple former of 9 power 0.5 +99 power 0

Answer 1

Hi ,

9^0.5 + 99^0

= ( 3² )^0.5 + 1

[ since a^0 = 1 ]

= (3^ 2× 0.5 )+ 1

= 3¹ + 1

= 3 + 1

= 4

I hope this helps you.

: )

Answer 2

$<h2><marquee behavior="alternate"><font color="Blue"><u>Hello</font> <font color="lime"><u>Friend</marquee></font></u></h2>$

9^0.5 + 99^0

= (3^2)^0.5 + 1

= (3)^2×0.5 +1

= 3^1 + 1

= 4

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