Simple interest and compound interest for a certain sum of money for two years is rs.500 and rs.648 respectively. what is the rate of interest?
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Answered by
0
SI: Px2xR/100 = 500..........(i)
CI: P(1+R/100)²- P =648 .................(ii)
On dividing (i) by (ii), we get
(2PR/100)÷(P(1+R/100)²- P) = 500/648
R²+200R-260=0
R = 1, - 201
So R = 1 %
CI: P(1+R/100)²- P =648 .................(ii)
On dividing (i) by (ii), we get
(2PR/100)÷(P(1+R/100)²- P) = 500/648
R²+200R-260=0
R = 1, - 201
So R = 1 %
Answered by
0
S.I = P×R×T/100
= 648 × 12 × 2/100
= 3888/25
= 155.52
A = P (1 + r/100)^t
= 648 (1 + 12/100)^2
= 648 × 112/100 × 112/100
= 8,128,512/10,000
= 812.8512
C.I = A - P
= 812.8512 - 648
= 164.8512
Difference = 164.8512 - 155.52
= 9.3312 ans.
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