Question

SIMPLE INTEREST FOR Rs.1000 AT 10% FOR 9 MONTHS IS

Answer 1

Here is your answer

$\rule{102}{2}$



Given :- Principal = Rs 1000

Rate of interest = 10%

Time = 9 months = $\frac{3}{4}$ years


To find :- Simple Interest


Solution :- We will use the formula of SI = $\frac{P*R*T}{100}$

By putting the values,

$\frac{1000*10*3/4}{100}$

By cancelling, we get,

10*10*$\frac{3}{4}$

=> 75

∴ Simple Interest = Rs 75

Answer 2

$<b>Heya mate. (^_-). Solution below.$
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• Given Principal (P) = 1000 Rs.


• Given Rate of interest (R) = 10% p.a.


• Given Time (T) = 9 months


• Since the rate is calculated per annum, we will change time into years.


• So, time -

= 9 months

= 9/12 years



• Then, Simple Interest (S.I.)

= (P × R × T)/100

= (1000 × 10 × 9/12)/100

= 1000 × 10 × 9/12 × 100

= 90000/1200

= 75.

Hence, the simple interest = 75 Rs.

$<marquee>Therefore, your answer is 75 Rs.</marquee>$
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Thank you.. ;-)