Simple interest is given by T- PPR . Il P= 8900)
2 years, and
the simple
100
Pa
R = 5% find
interest.
Answers
Answer:
Given:
Principal (P) = ₹8900
Amount (A) = ₹9801
Time (T) = 2 years
To Find:
Rate of Interest (R) = ??
Formula Used:
\red{\boxed{\sf{R = \dfrac{100\times SI}{P\times T}}}}
R=
P×T
100×SI
Solution:
As, P = ₹8900 and A = ₹9801
Therefore, Simple Interest (SI) = ₹ (A - P)
= ₹ (9801 - 8900)
= ₹ 901
Simple Interest (SI) = ₹ 901
Therefore,
\begin{gathered}\sf{R = \dfrac{100\times SI}{P\times T}}\\\\\sf{= \dfrac{1\!\!\!\not{0}\!\!\!\not{0}\times 901}{89\!\!\!\not{0}\!\!\!\not{0}\times 2}}\\\\\sf{= \dfrac{901}{178}}\\\\\sf{=5 \dfrac{11}{178}}\end{gathered}
R=
P×T
100×SI
=
89
0
0×2
1
0
0×901
=
178
901
=5
178
11
Hence, Rate of Interest = \sf{5 \dfrac{11}{178}\%}5
178
11
%