Math, asked by singhmeera064, 3 months ago

simple interest on 800 for 2 years at 10% per annum​

Answers

Answered by kanak8398
0

Answer:

A=P*R/T

A= 800*10/1

A = 8000

Now,

A= P*R/T

A= 8000*10/1

A = 80000

Therefore, C.I = (80000-8000)

= 71000

Step-by-step explanation:

Hope it's help u

Answered by FιҽɾყPԋσҽɳιx
38

\bf Question

The simple interest on ₹ 800 invested for 10% per annum for 2 years is ___.

\bf To \: Find

We have to find simple interest

Answer:

The simple interest is ₹240

Step-by-step explanation:

Simple interest on ₹ 800 means Principal is ₹ 800 and Rate is 10% time period is 2 years

We have to find simple interest

\bf \: Formula \: used

\: \: \: \: \: \: \: \underline{ \boxed{ \rm S.I = \dfrac{P \times R \times T}{100} }}

Where,

S.I = Simple interest

P = Principal

R = Rate

T = Time

Now,

P = Rs. 800

R = 10%

T = 3

Now, put values in formula

\begin{gathered}\begin{gathered} \implies \bf S.I = \dfrac{P \times R \times T}{100} \\ \\ \end{gathered} \end{gathered}

\begin{gathered}\begin{gathered} \implies\bf S.I = \dfrac{800 \times 10 \times 2}{100} \\ \\ \end{gathered} \end{gathered}

\begin{gathered}\begin{gathered}\implies\bf S.I = \dfrac{8 \cancel{ 00} \times 10 \times 2}{1 \cancel{00}} \\ \\ \end{gathered} \end{gathered}

\begin{gathered}\begin{gathered}\implies\bf S.I =8 \times 10 \times 2 \\ \\ \end{gathered} \end{gathered}

\begin{gathered}\begin{gathered}\implies\bf S.I =8 \times 10 = 80 \\ \\ \end{gathered} \end{gathered}

\implies\bf S.I = 80\times 3

\implies\bf S.I = ₹ \: 240

Required Answer :-

The simple interest is ₹240.

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