Math, asked by veeru112, 1 year ago

Simple interest on a certain  sum of money for 3 years  at 18% per annum is half the compound interest on Rs. 9000 for 2 years  at 10% per annum. The sum placed on simple  interest is:

Options:

1) Rs 3500

2) Rs 875

3) Rs 1750

4) Rs 1400

Answers

Answered by gravitation1
17
so the answer is option C. I hope this will clear your doubts related to this question .
Attachments:
Answered by pinquancaro
3

Answer:

Option 3 - The required sum placed on simple interest is Rs.1750.                  

Step-by-step explanation:

Given : Simple interest on a certain  sum of money for 3 years  at 18% per annum is half the compound interest on Rs. 9000 for 2 years  at 10% per annum.

To find : The sum placed on simple interest is ?

Solution :

The compound interest formula is CI=A-P

Where, A=P(1+r)^t

A is the amount

P is the principal P=9000

r is the interest rate r=10%=0.1

t is the time t=2 years

Substitute the value in the formula,

A=P(1+r)^t

A=9000(1+0.1)^2

A=9000(1.1)^2

A=9000(1.21)

A=10890

Compound interest is

CI=10890-9000

CI=1890

Simple interest on a certain sum of money for 3 years  at 18% per annum is half the compound interest.

i.e. Simple interest = \frac{1890}{2}=945

R=18%=0.18

T=3 years

Using simple interest formula,

S.I=Sum\times R\times t

Sum=\frac{S.I}{R\times T}

Sum=\frac{945}{0.18\times 3}

Sum=\frac{945}{0.54}

Sum=1750

Therefore, The required sum placed on simple interest is Rs.1750.

So, Option 3 is correct.

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