simple interest on certain sum of money for 4years at 4% per annum exceeds the compound interest on the same sum for 3 years at 5% per annum by 225rs. find the sum?
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Answered by
45
Principal = P
Simple interest = P * 4/100 * 4 years = 0.16 P
Compound interest = P * (1 + 5/100)³ = 1.157625 P - P = 0.157625 P
Given, 0.16 P - 0.157625 P = Rs 225
P = Rs 94,736. 84
Simple interest = P * 4/100 * 4 years = 0.16 P
Compound interest = P * (1 + 5/100)³ = 1.157625 P - P = 0.157625 P
Given, 0.16 P - 0.157625 P = Rs 225
P = Rs 94,736. 84
anshkhanna786:
Ans is 96000 but how??
then the Difference in the interests is not Rs 225, but it is Rs 228. please check if you have entered data correctly. If SI - CI = Rs 228, then Principal sum = Rs 96,000.
My solution is not wrong. you have unnecessarily reported. please ask for confirmation. it is correct.
Answered by
10
Step-by-step explanation:
Simple interest on a certain sum of money for
4 years at 4% per annum exceeds the
compound interest on the same sum for 3
years at 5 percent per annum by * 228. Find
the sum
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