Question

Simple interest on Rs 7500 for 10years at the rate of 13% is

Answer 1

Answer :-

• The simple interest is Rs 9750.

Given :-

• Principal = Rs 7500.
• Rate = 13% per annum.
• Time = 10 years.

To find :-

• The simple interest.

Step-by-step explanation :-

• The question has given us the principal, rate and time. We have to find the simple interest. For this, we are going to use the formula required for finding the simple interest and then apply it to find our answer.

Calculations :-

We know that :-

$\underline{\boxed{ \sf Simple \: Interest = \frac{P \times R \times T}{100}}}$

Here,

P = Principal.

R = Rate of interest.

T = Time.

Simple Interest can also be written as SI.

Now let's apply this formula.

Substituting the given values,

$\tt SI = \dfrac{75 \!\!\!\not0 \!\!\!\not0 \times 13 \times 10}{1\!\!\! \not0 \!\!\!\not0}$

• Cutting off the zeroes,

$\tt SI = \dfrac{75 \times 13 \times 10}{1}$

• Now let's multiply the remaining numbers.

$\tt SI = 75 \times 13 \times 10$

• Multiplying the numbers,

$\tt SI = 9750.$

-----------------------------------------------------------

• Hence, the simple interest on Rs 7500 for 10 years at the rate of 13% per annum is Rs 9750.

Answer 2

Answer:

We know,

$\: \: \: \: \: { \boxed{{\sf \:simple \: interest = \dfrac{p \times r \times t}{100} } }}\\ \\ \\ \\ \therefore \: \sf \: p = Rs 7500 \\ r = 13 \\ \sf t = 10\:years\\ \\ \\ \\ \sf \: calculating... \\ \\ \sf \:simple \: interest = \dfrac{p \times r \times t}{100}$

$\sf \:simple \: interest = \dfrac{7500 \times 13 \times 10}{100}$

$\:\sf \:simple \: interest = \dfrac{75 \cancel{00} \times 13 \times 10} {\cancel{100}} \\ = 75 \times 13 \times 10 \\ \boxed{\bold{\blue{ = 9750}}}$

Correct Answer:-

• $\sf\boxed{\bold{\red{Interest = Rs\:9750}}}$