Simple Math Puzzle on triangles.
ABCD is a square. Green circle's radius = 2 cm. Blue circle has a radius = 4 cm.
Find the length "a" of the edge of the square.
Use the formulas related to triangles.
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Answered by
20
Hey there,
PF = KO = KF = 4cm
BP = BT ; CK = CT =[ Tangents to a circle from common point ]
Perimeter [ BFC ] = BP + PF + KF + KC + BC
Perimeter [ BFC ] = ( BT + CT ) + PF + KF + BC
Perimeter [ BFC ] = a + a + 4 + 4
Perimeter [ BFC ] = 2a + 8
16[ 2a + 8 ]/2 + 16 = a²
16a + 64 + 16 = a²
a² - 16a - 80 = 0
a = 20, -4
Hence, a = 20 is the solution.
Hope this helps!
PF = KO = KF = 4cm
BP = BT ; CK = CT =[ Tangents to a circle from common point ]
Perimeter [ BFC ] = BP + PF + KF + KC + BC
Perimeter [ BFC ] = ( BT + CT ) + PF + KF + BC
Perimeter [ BFC ] = a + a + 4 + 4
Perimeter [ BFC ] = 2a + 8
16[ 2a + 8 ]/2 + 16 = a²
16a + 64 + 16 = a²
a² - 16a - 80 = 0
a = 20, -4
Hence, a = 20 is the solution.
Hope this helps!
Answered by
20
Nice question.
Answer explained below.
Comment below if any doubt occurs to you.
#OriginalAnswer
#NoCopy
Answer explained below.
Comment below if any doubt occurs to you.
#OriginalAnswer
#NoCopy
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