Simple Math Puzzle on triangles.
ABCD is a square. Green circle's radius = 2 cm. Blue circle has a radius = 4 cm.
Find the length "a" of the edge of the square.
Use the formulas related to triangles.
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supersonu:
sir it is too difficult...
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Answered by
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hiii..
PF = KF = 4CM
Perimeter OF BFC = BP + PF + KF+ KC
Perimeter [ BFC ] = ( BT + CT ) + PF + KF + BC
Perimeter [ BFC ] = a + a + 4 + 4
Perimeter [ BFC ] = 2a + 8
AND
...............
16[ 2a + 8 ]/2 + 16 = a²
16a + 64 + 16 = a²
a² - 16a - 80 = 0
a = 20, -4
I HOPE THIS HELPS U
PLS MARK ME BRAINLEST
PF = KF = 4CM
Perimeter OF BFC = BP + PF + KF+ KC
Perimeter [ BFC ] = ( BT + CT ) + PF + KF + BC
Perimeter [ BFC ] = a + a + 4 + 4
Perimeter [ BFC ] = 2a + 8
AND
...............
16[ 2a + 8 ]/2 + 16 = a²
16a + 64 + 16 = a²
a² - 16a - 80 = 0
a = 20, -4
I HOPE THIS HELPS U
PLS MARK ME BRAINLEST
Answered by
1
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