Question

Simple Question!!!!

A train travels 126 km in 1 hour 30 minutes with a certain speed. How many kilometres it will travel in 4 hours 45 minutes with the same speed?

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Answer 1

Question:—

A train travels 126 km in 1 hour 30 minutes with a certain speed. How many kilometres it will travel in 4 hours 45 minutes with the same speed?

Answer:—

• 399 km

Step by step Explanation:—

Here we know that

• 1 hour 30 minutes = 90 minutes
• 4 hour 45 minutes = 285 minutes

So,

Distance traveled in 90 minutes = 126 km

Then,

Distance traveled in 1 minute = 126/90

Again,

Distance traveled in 285 minutes

• = 126 × 285/90
• = 35910/90
• = 399 km

Hope it helps you.

Answer 2

$\green{\large\underline{\sf{Solution-}}}$

Given that,

• A train travels 126 km in 1 hour 30 minutes with a certain speed.

Let suppose that

• Car travel x km in 4 hour 45 minutes with the same speed.

So, using Concept of Direct variation,

As, More time, more distance travelled.

So,

$\begin{gathered}\boxed{\begin{array}{c|c|c} \bf Distance & \bf 126 & \bf x\\ \frac{\qquad}{} & \frac{\qquad}{}\frac{\qquad}{} & \frac{\qquad}{} &\\ \bf Time & \sf 90 \: min & \sf 285 \: min \\ \end{array}} \\ \end{gathered}$

So, using Direct variations, we have

$\rm :\longmapsto\:\dfrac{126}{90} = \dfrac{x}{285}$

$\rm :\longmapsto\:\dfrac{42}{30} = \dfrac{x}{285}$

$\rm :\longmapsto\:\dfrac{7}{5} = \dfrac{x}{285}$

$\rm :\longmapsto\:\dfrac{7 \times 285}{5} = x$

$\rm \implies\:x = 57 \times 7 = 399 \: km$

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Indirect variation :- The variation between x and y is called Indirect variation if with the increase in x, there is decrease in y or vice versa.

Direct variation :- The variation between x and y is called direct variation if with the increase in x, there is increase in y or vice versa.