Question

Simple Question


The cost of fencing a garden
which is in the shape of a trapezium is ₹11250 at the rate of ₹50 per metre. Find its height if its parallel sides are 20 m and 25 m long.

__________________________

Thank you!​

Answer 1

Answer:

$11250 \div 50 = 225 \\ 20 \times 25 = 500 \\ 500 \div 225 = 2.222 \: answer \:$

Answer 2

Answer:

$area \: of \: trapezium \: = 11250 \div 50 = 225 {m}^{2} \\ \frac{1}{2 } \times (sum \: of \: the \: parallel \: sides \: ) \times height \: = 225 \\ \frac{1}{2} \times (20 + 25) \times height \: = 225 \\ height \: = 10m$