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area of circular road =π(15)^2
area of inside path of wide 2m= π(15)^2 -π(13)^2 =π*28*2=π*56=(22/7)*56=172sqm
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area of inside path of wide 2m= π(15)^2 -π(13)^2 =π*28*2=π*56=(22/7)*56=172sqm
mark it as brainliest answer
Navasaan:
sorry answer is 176.
a small error in calculations
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Area of circular park=πr²
=22/7×15²
=22/7×225
=707.14m²
A road 2m wide inside it
so, it's radius =15-2=>13m
Area=πr²
=22/7×13²
=22/7×169
=531.14
Area of road=707.14-531.14=>176m²
=22/7×15²
=22/7×225
=707.14m²
A road 2m wide inside it
so, it's radius =15-2=>13m
Area=πr²
=22/7×13²
=22/7×169
=531.14
Area of road=707.14-531.14=>176m²
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