Question

Simplest factor of roort 48

Answer 1

Answer:

$\sqrt[4]{3}$

Step-by-step explanation:

first step is to do prime factorization

2|48

2|24

2|12

2|6

3|3

  1

48=2*2*2*2*3

     = $2^{2}*2^{2}$*3

when we take sq.root

$\sqrt{48$ =$\sqrt{2^{2}*2^{2}*3 }$

      =$\sqrt[4]{3}$