Question

simplest rationalising factor

Answer 1

Hi friend, Harish here.

Here is your answer:

$\sqrt[3]{49} = \sqrt[3]{7^{2}}$

So, the rationalizing factor is ∛7. 

Because,

$\sqrt[3]{7^{2}}= 7^{ \frac{2}{3}} = 7^{ \frac{2}{3}} \times \frac{7^{ \frac{1}{3}} }{7^{ \frac{1}{3}}}$

→ $\frac{7}{7^{ \frac{1}{3}}} = \frac{7}{ \sqrt[3]{7} }$

Hence it number is rationalized . 

Therefore ∛7 is the rationalizing factor.
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Hope my answer is helpful to you.

Answer 2

Answer:

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