Question

simplest way to solve quadratic equation?
like x²+10x-8= 0​

Answer 1

EXPLANATION.

Solve quadratic equation.

⇒ x² + 10x - 8 = 0.

As we know that,

⇒ D = discriminant Or b² - 4ac.

⇒ D = (10)² - 4(1)(-8).

⇒ D = 100 + 32.

⇒ D = 132.

⇒ x = - b ± √D/2a.

⇒ x = - 10 ± √132/2.

⇒ x = - 10 ± 2√33/2.

⇒ x = 2(- 5 ± √33)/2.

⇒ x = - 5 ± √33.

                                                                                                               

MORE INFORMATION.

Nature of the roots of the quadratic expression.

(1) Roots are real and unequal, if b² - 4ac > 0.

(2) Roots are rational and different, if b² - 4ac is a perfect square.

(3) Roots are real and equal, if b² - 4ac = 0.

(4) If D < 0 Roots are imaginary and unequal Or complex conjugate.

Answer 2

Given :

A quadratic equation $x^{2} +10x-8=0$

To find :

The zeros of the quadratic equation.

Step-by-step explanation:

• The zeros of this given quadratic equation can be found by using this formula

       $-b$ ± $\frac{\sqrt{b^{2} -4ac}}{2a}$

• From the given equation, we know that

        $a=1,b=10,c=-8$

• Substitute these values in the given expression

        $-10$ ± $\frac{\sqrt{(10)^{2}-4(1)(-8) }}{2(1)}$

• Remove the brackets

        $-10$ ± $\frac{\sqrt{100 +32} }{2}$

• Sum it all up
• Then, the equation will be

        $-10$ ± $\frac{\sqrt{132}}{2}$

• Take the root of the number

        $-10$ ± $\frac{11.4}{2}$

• Divide the values

        $10$ ± $5.7$

• The zeros would become

        $10-5.7,10+5.7$

• The final answer would become

        $4.3 , 15.7$

Final answer :

The zeros of the equation would be $4.3 , 15.7$