Question

simplfy (1+root2 /1-root 3)+(1-root 2/1+root3)​

Answer 1

this the answer of your question

-1-root6

Answer 2

-(1+√6)

• (1+√2)/(1-√3)=(1+√2)(1+√3)/(-2)

=(1+√3+√2+√6)/(-2)

• (1-√2)/(1+√3)=(1-√2)(√3-1)/2

=(√3-1-√6+√2)/2

So,

(1+√2)/(1-√3)+(1-√2)/(1+√3)

(1+√2)/(1-√3)+(1-√2)/(1+√3) =(√3-1-√6+√2)/2 + (1+√3+√2+√6)/(-2)

(1+√2)/(1-√3)+(1-√2)/(1+√3) =(√3-1-√6+√2)/2 + (1+√3+√2+√6)/(-2) =(√3-1-√6+√2-1-√3-√2-√6)/2

(1+√2)/(1-√3)+(1-√2)/(1+√3) =(√3-1-√6+√2)/2 + (1+√3+√2+√6)/(-2) =(√3-1-√6+√2-1-√3-√2-√6)/2 =(-2-2√6)/2

(1+√2)/(1-√3)+(1-√2)/(1+√3) =(√3-1-√6+√2)/2 + (1+√3+√2+√6)/(-2) =(√3-1-√6+√2-1-√3-√2-√6)/2 =(-2-2√6)/2 =-(1+√6) (Ans)