Question

simplfy (2-¹*4-¹)*2-²

Answer 1

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Answer 2

$Value \:of \: ( 2^{-1} \times 4^{-1} ) \div 2^{-2}$

$= \frac{( 2^{-1} \times 4^{-1} ) }{2^{-2}}$

$= \frac{ 2^{2}}{2^{1} \times 4^{1}}$

$\blue { (By \: Exponential \:Law : )}$

$\boxed { \pink { a^{-n} = \frac{1}{a^{n}} }}$

$= \frac { 4}{8} \\=\frac{1}{2}$

Therefore.,

$\red { Value \:of \: ( 2^{-1} \times 4^{-1} ) \div 2^{-2}} \green {= \frac{1}{2} }$

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