simpli each of the following expression as log N 2) 3log 4
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i) log 2 + log 5
logm+logn=log(m*n)=logNlogm+logn=log(m∗n)=logN
log2+log5=log(2*5)=logNlog2+log5=log(2∗5)=logN =log10
So, N=10
(ii) log 16 - log 2
logm-logn=log(m/n)=logNlogm−logn=log(m/n)=logN
log16-log2=log(16/2)=logNlog16−log2=log(16/2)=logN =log8
Hence, N =8
(iii) 3 log 4
xlogy=logy^{x}xlogy=logy
x
3log4=log4^{3}3log4=log4
3
=log64=logN
N =64
(iv) 2 log 3 - 3 log 2
2log3=log3^{2}2log3=log3
2
=log9
3log2=log2^{3}3log2=log2
3
=log8
log9-log8=log(9/8)=log(1.125)
N=1.125
(v) log243 + log1
log1=0
So,log243 + log1 =log243=logN
N=243
(vi) log 10 + 2 log 3 - log 2
2log3=log3^{2}2log3=log3
2
=log9
log9-log2=log(9/2)=log4.5
log4.5+log10=log45=logN
N=45.
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