Question

simplicity x^3÷x-y + y^3÷y-x
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Answer 1

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$\frac{ {x}^{3} }{x - y} + \frac{ {y}^{3} }{y - x} \\ = \frac{ {x}^{3} }{x - y} - \frac{ {y}^{3} }{x - y} \\ = \frac{ {x}^{3} - {y}^{3} }{x - y} \\ = \frac{(x - y)( {x}^{2} + xy + {y}^{2} )}{x - y} \\ {x}^{2} + xy + {y}^{2}$

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