Question

simplied
please solve this exponents and powers class 7 maths chapter 13
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Answer 1

Answer:

(18² x 3⁹ x t¹⁵)/(6³ x 2⁸ x t⁹)

={(2 x 3 x 3)² x 3⁹ x t¹⁵}/ {(2 x 3)³ x 2⁸ x t⁹}

=(2² x 3² x 3² x 3⁹ x t¹⁵)/ (2³ x 3³ x 2⁸ x t⁹)

={(3^2 + 2 + 9) x 2² x t^15 - 9} / {(2^ 3 + 8) x 3³}

={( 3^13 - 3) x 2² x t⁶} / (2 ^ 12)

=3¹⁰ x 2^2 - 12 x t⁶

=3¹⁰ x 2^-10 x t⁶

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