Math, asked by jagrteebaser191986, 2 months ago

simplifie:(6x+7y)(5x+4y)​

Answers

Answered by preeti353615
0

Answer:

(6x+7y)(5x+4y) ​= 30x^2 + 59 xy + 28y^2

Step-by-step explanation:

(6x+7y)(5x+4y)​

The first number of the first bracket multiply to the second bracket, then the second number of the first bracket multiply to the second bracket.  

= 6x(5x+ 4y) + 7y (5x+ 4y)

Multiply each number in bracket

= 6x (5x) + 6x (4y) + 7y (5x) + 7y (4y)

= 30x^2 + 24 xy + 35 xy + 28y^2\\= 30x^2 + (24+ 35) xy + 28y^2\\= 30x^2 + 59 xy + 28y^2

Answered by yassersayeed
0

Answer:

The required value of (6x+7y)(5x+4y)=30x^{2} +59xy+28y^{2}

Step-by-step explanation:

In accordance with the information provided in the question,

We have find the value of the supplied expression in the above question.

Given the data in question (6x+7y)(5x+4y)​

As the given equation is in form of (a+b)(a+b)

So, for finding the value of the expression we will first multiply "a" with "c" and a with  "d" and then multiply "b" with "c" and b with "d", and then add the resultant value.

So, value of expression we will be

ac+ad+bc+bd

(6x+7y)(5x+4y)=(6x\times 5x)+(6x\times 4y)+(7y\times 5x)+(7y\times 4y)\\30x^{2} +24xy+35yx+28y^{2} \\30x^{2} +24xy+35xy+28y^{2} \\30x^{2} +59xy+28y^{2}

Hence required value of (6x+7y)(5x+4y)=30x^{2} +59xy+28y^{2}

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