Question

Simplified 1/√7+5 class 9th Question​

Answer 1

Answer:

$\frac{\sqrt{7}-5 }{-18}$

Step-by-step explanation:

$\frac{1}{\sqrt{7} +5}(\frac{\sqrt{7} -5}{\sqrt{7}-5} ) \\\\= \frac{{\sqrt{7}-5}}{(\sqrt{7})^2 - 5^2} \\\\=\frac{\sqrt{7} -5}{7-25} \\\\=\frac{\sqrt{7}-5 }{-18}$

Answer 2

Answer:

root2/24

Step-by-step explanation:

First rationalize the denominator

$\frac{1}{\sqrt{7+5} } *\frac{\sqrt{7-5} }{\sqrt{7-5} } \\=\frac{\sqrt{7-5} }{(7+5)(7-5)} \\=\frac{\sqrt{2} }{7^{2}-5^{2} } \\=\frac{\sqrt{2} }{24}$

You can further simplify this if you want so.